✓ Solved: The magnetic moment of the Earth is approximately 8.00× 10^22A·m^2. Imagine that the planetary...
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The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to - YouTube
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The magnetic moment of the assumed dipole at the earth's centre is `8.0 xx 10^22 A m^2`. Calculate - YouTube
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Solved The earth's magnetic moment is 8 x 1022 A-m2. If that | Chegg.com
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The magnetic field of earth at the equator is approximately 4 × 10^-5T . The radius of earth is 6.4 × 10^6m . Then the dipole moment of the earth will be nearly of the order of :
SOLVED:The magnetic moment of the Earth is approximately 8.00 \times 10^{22} \mathrm{A} \cdot \mathrm{m}^{2} (a) Imagine that the planetary magnetic field were caused by the complete magnetization of a huge iron deposit.
An electron is moving in a cyclotron at a speed of 3.2 × 10^7 m s^-1 in a magnetic field of 5 × 10^4 T perpendicular to it. What is the frequency
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